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	<title>Comments on: Can you help me with this extra credit problem ALGEBRA?</title>
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	<link>http://www.safedebthelp.com/blog/can-you-help-me-with-this-extra-credit-problem-algebra/</link>
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	<pubDate>Fri, 18 May 2012 01:24:16 +0000</pubDate>
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		<title>By: whatever comes</title>
		<link>http://www.safedebthelp.com/blog/can-you-help-me-with-this-extra-credit-problem-algebra/comment-page-1/#comment-3096</link>
		<dc:creator>whatever comes</dc:creator>
		<pubDate>Sun, 18 Jul 2010 20:01:11 +0000</pubDate>
		<guid isPermaLink="false">http://www.safedebthelp.com/blog/can-you-help-me-with-this-extra-credit-problem-algebra/#comment-3096</guid>
		<description>so the LCD is (4x^2 - 1) right? that'll be the denominator for the fraction on the left. using that LCD as the new denominator, let's simplify the new numerator....

(2x + 1) (x + 2) + (2x - 1) (5x), so
(2x^2 + 5x + 2) + (10x^2 - 5x), then combine similar terms,
12x^2 + 2 ---&gt; the new numerator.

now let's put the whole thing together:

12x^2 + 2
________   = -2 , then cross-multiply the denominator 
                                                        
 4x^2 - 1


12x^2 + 2 = -8x^2 + 2, then combine similar terms again
20x^2 = 0, so
x = 0


please double-check everything. at least now you get the basic steps in solving this problem. hope i've helped you understand how to do this in the future.&lt;a href="http://www.safedebthelp.com/help-me-get-out-of-debt.htm"&gt; whatever comes&lt;/a&gt;</description>
		<content:encoded><![CDATA[<p>so the LCD is (4x^2 - 1) right? that&#8217;ll be the denominator for the fraction on the left. using that LCD as the new denominator, let&#8217;s simplify the new numerator&#8230;.</p>
<p>(2x + 1) (x + 2) + (2x - 1) (5x), so<br />
(2x^2 + 5x + 2) + (10x^2 - 5x), then combine similar terms,<br />
12x^2 + 2 &#8212;> the new numerator.</p>
<p>now let&#8217;s put the whole thing together:</p>
<p>12x^2 + 2<br />
________   = -2 , then cross-multiply the denominator </p>
<p> 4x^2 - 1</p>
<p>12x^2 + 2 = -8x^2 + 2, then combine similar terms again<br />
20x^2 = 0, so<br />
x = 0</p>
<p>please double-check everything. at least now you get the basic steps in solving this problem. hope i&#8217;ve helped you understand how to do this in the future.<a href="http://www.safedebthelp.com/help-me-get-out-of-debt.htm"> whatever comes</a></p>
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		<title>By: The Scarlet Pumpernickel</title>
		<link>http://www.safedebthelp.com/blog/can-you-help-me-with-this-extra-credit-problem-algebra/comment-page-1/#comment-3095</link>
		<dc:creator>The Scarlet Pumpernickel</dc:creator>
		<pubDate>Sat, 17 Jul 2010 17:01:16 +0000</pubDate>
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		<description>The way you typed the problem is unclear to me. Please repost this question and make the problem a little bit easier to understand if you'd like help!&lt;a href="http://www.resumeminers.com/online-degree/master-online-degree.htm"&gt; The Scarlet Pumpernickel&lt;/a&gt;</description>
		<content:encoded><![CDATA[<p>The way you typed the problem is unclear to me. Please repost this question and make the problem a little bit easier to understand if you&#8217;d like help!<a href="http://www.resumeminers.com/online-degree/master-online-degree.htm"> The Scarlet Pumpernickel</a></p>
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