Can you help me with this extra credit problem ALGEBRA?
.wuzzy. asked:
Another extra credit question. Teacher wont help because its EC
I found the LCD but
I get lost in the middle of the problem
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Another extra credit question. Teacher wont help because its EC
I found the LCD but
I get lost in the middle of the problem
here it is
x+2 5x
—– + —– = -2
2x-1 2x+1
I need to show all work and need this grade. Any help very appreciated.
ok it came out different
its
x+2/2x-1 + 5x/2x+1 = -2
sorry
July 17th, 2010 at 12:01 pm
The way you typed the problem is unclear to me. Please repost this question and make the problem a little bit easier to understand if you’d like help! The Scarlet Pumpernickel
July 18th, 2010 at 3:01 pm
so the LCD is (4x^2 - 1) right? that’ll be the denominator for the fraction on the left. using that LCD as the new denominator, let’s simplify the new numerator….
(2x + 1) (x + 2) + (2x - 1) (5x), so
(2x^2 + 5x + 2) + (10x^2 - 5x), then combine similar terms,
12x^2 + 2 —> the new numerator.
now let’s put the whole thing together:
12x^2 + 2
________ = -2 , then cross-multiply the denominator
4x^2 - 1
12x^2 + 2 = -8x^2 + 2, then combine similar terms again
20x^2 = 0, so
x = 0
please double-check everything. at least now you get the basic steps in solving this problem. hope i’ve helped you understand how to do this in the future. whatever comes